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whiCh no

whichever 既可以引导名词性从句也可以引导让步状语从句,引导让步状语从句时可以转换成no matter which。 no matter which 只可以引导让步状语从句。 例如: Either Friday or Monday --- choose whichever day is best for you.(名词性从句) ...

no matter which和whichever都引导让步状语从句 whichever可引导名词性从句,而no matter which 则不能 如。No matter which girl wins, we should be happy让步状语从句 =Whichever girl wins , we should be happy Whichever girl will win (...

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whichever 既可以引导名词性从句也可以引导让步状语从句,引导让步状语从句时可以转换成no matter which。 no matter which 只可以引导让步状语从句。 例如: Either Friday or Monday --- choose whichever day is best for you.(名词性从句) ...

no matter which 只能引导让步状语从句 ,而whichever既可引导让步状语从句又可引导其他名次性从句(如定语从句) NO matter which one you choose ,I will suppor you.(可以用whichever替换) I will support your choice whichever you make.(...

#include #include #include //加入这行 using namespace std; 如果没有包含的话,cout不支持string类型的数据。

这个错误显示没有定义+号操作。不是所有类型都支持+号操作,有些自定义类型(比如类)应该重载+号操作。 怎么改正问题?具体应该看一下代码是否用了隐式的类型转换,对于隐式转换的类型尽量先转换在运算。 如果还是不能解决问题,附上关键代码吧。

#include // 不要加.h #include int main() { using std::string; using std::cin;// 如果不想用using namespace std,那么每个名字都要using using std::cout; using std::endl; string word; while(std::cin>>word) std::cout

少了#include

whatever就相当于no matter what,只是no matter what只能引导让步状语从句,而不能引导名词性从句,whatever则是两者都可以.表达的意思就是这一类种的任何.如 I will do whatever you ask me to do. No matter what you ask me to do,I will do it...

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